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Die Inhalte von Opencaching.de stehen unter der Creative-Commons-Lizenz BY-NC-ND 3.0 DE.

Richtig Sichere Angelegenheit

Bob needs your help! Please help him decrypt the secret message!

door BafTux Oostenrijk > Wien > Wien

N 48° 15.689' E 016° 23.811' (WGS84)
andere coördinaatstelsel Grootte: micro Status: Beschikbaar Verborgen op: 15.06.2022 Published on: 07.04.2026 Laatste verandering: 07.04.2026 Listing: https://opencaching.de/OC18C6F Ook gepubliceerd op: geocaching.com	0 Gevonden 0 Niet gevonden 0 Opmerkingen 1 Watcher 0 Negeerders 18 Bekeken 0 Log pictures Geokrety verleden

Large map

Seasonal

Preparation needed

Beschrijving Deutsch · English (Engels)

Changelog

2022-06-15 - Initial release (gc only)
2026-04-07 - Publish on oc; No content changes.

Description

Bob needs your help! He and Alice are communicating via encrypted texts and Bob just received a new message from Alice:

WUaPSMWHPjsZ/t0MPYksZsfxH2en56TDyu+9CUirg/l4c5yqQxeUG8hmIYYsB7nU6XUaM1yzMp3gVco9w+olvw==

Unfortunately, Bob has forgotten the private key to decrypt the message. However, he still has the self-implemented source code of the decryption tool. Can you help Bob to recover the original message from Alice?

import base64

def main():

print('Richtig Sicherer Austausch (v1.0 - 2022-06-05)')

cipher = read_cipher("WUaPSMWHPjsZ/t0MPYksZsfxH2en56TDyu+9CUirg/l4c5yqQxeUG8hmIYYsB7nU6XUaM1yzMp3gVco9w+olvw==")

# This line asks for the key on the command line

# key = read_key()

# You can also directly pass in the key:

key = read_key(17)

decrypt(cipher, key)

def decrypt(cipher, key):

cipher_num = int.from_bytes(cipher, byteorder='big')

# Remember, e = 0x10001, Hopefully no one knows the prime factors of this number

modulus = 10941738641570527421809707322040357612003732945449205990913842131476349984288934784717997257891267332497625752899781833797076537244027146743531593354333897

plain_num = pow(cipher_num, key, modulus)

plain_bytes = plain_num.to_bytes( (plain_num.bit_length() + 7) // 8, byteorder='big')

try:

plain_text = plain_bytes.decode('utf8')

print(f'plaintext = {plain_text}')

except UnicodeDecodeError:

print('Failed to decrypt message. Wrong key!?')

def read_cipher(cipher=None):

"""

Reads the base64 encoded cipher and converts it into a byte array

"""

if cipher is None:

cipher = input('Enter the ciphertext: ')

decoded = base64.b64decode(cipher)

return [bb for bb in decoded]

def read_key(key=None):

if key is None:

key = input('Enter the key (in base 10): ')

return int(key)

if __name__ == '__main__':

main()

Further information

Brute-Force is not necessary. The result should be unambiguous. You dont have to modify the given decryption code, you only have to provide the correct key.

Acknowledgements

Thanks to the beta testers for testing & their feedback.

AimyBits
Dementophobia

Gecodeerde hint Decoderen

[puzzle] Eba, Nqv, naq Yrbaneq pna uryc lbh. Urezna naq uvf grnz cebonoyl nf jryy.
[cache] Frr zrffntr sebz Nyvpr

A|B|C|D|E|F|G|H|I|J|K|L|M
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

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